Cliff gets a WSM for Christmas

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Bruce B said:
[quote="Nick Prochilo":3l34nvc0]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:[/quote:3l34nvc0]

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:
 
Finney said:
Bruce B said:
[quote="Nick Prochilo":74pmogx1]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:[/quote:74pmogx1]
A couple of aspirin :shock:
 
okay, I settled it. drilled a hole and stuck a therm in it. Now its done.

pic1pr1.jpg
 
Finney said:
Bruce B said:
[quote="Nick Prochilo":35kqflbj]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:[/quote:35kqflbj]

Finney's math is complicated, but his answer is wrong.*
The area of a circle varies directly as the square of its diameter. So, you can just leave out the pi's from the equations and compare the squares of the diameters. For example, a one-inch circle has an area 4 times that of a 1/2 inch circle. Or, 16 times the area of a 1/4 inch circle. For the one inch diameter hole: d^2 = 1.
For the 1/4 inch probe, d^2 = 0.25 x 0.25 = 0.0625, or 6.25% of the area of the one inch hole. And, since we have 3 of those holes, 6.25% divided by 3 equals 2.08% So, your 1/4 inch probe only blocks 2.08% of the vent area of the three one-inch holes.

[smilie=a_tongue.gif]

*Area of 1/4 inch circle: 0.25 inch x 25.4 mm/inch = 6.35 mm dia. or 3.175 mm radius (roughly). A = pi x r^2 or 3.14etc x (3.175) x (3.175) = 31.669 sq. mm., not 82.1699 And 31.669 divided by 1520.122 = 0.0208
 
Bill The Grill Guy said:
okay, I settled it. drilled a hole and stuck a therm in it. Now its done.
How'd you start the hole without (a) centerpunching and chipping more enamel than intended, or (b) skating and skitching all over the lid with a runaway drill? ;)

--John 8)
(You see, I've thought about it, but haven't done it yet. :roll: )
 
Well I'll keep it simple...you adjust to your working environment.

Bill, with all respect. I was a fireman for 5 1/2 years. Fire requires 3 elements to exist; heat, oxygen and fuel. When a house in on fire you cut a hole in a roof to control, hopefully contain a fire to a specific area, therefore giving the fire more oxygen from above and creating a draft. The fire then burns towards the hole in the roof; heat rises and the fuel (the house) last longer. Correct me if I'm wrong.

Is there an optimum measurement to what size the hole in the roof should be based on the burning area? Maybe there is. I'm not sure what that formula is (Finney probably knows :twisted: ) but what I do know is you do what you can with what you have to work with at the time. Just like cooking in comps.

My point is, for me, my WSM worked great right out the box with no mods. That’s all. Do what you think works best for you. It’s your cooker. You have the right to do what you want with you WSM. Drill, cut, rivet, screw and weld away. Its not the cooker, it is the cook that wins.
 
Unity said:
Bill The Grill Guy said:
okay, I settled it. drilled a hole and stuck a therm in it. Now its done.
How'd you start the hole without (a) centerpunching and chipping more enamel than intended, or (b) skating and skitching all over the lid with a runaway drill? ;)

--John 8)
(You see, I've thought about it, but haven't done it yet. :roll: )

A couple layers of masking tape will help keep the bit from wandering. It is easy to do, just don't see a need to do it to mine.

Bill, install looks good. Good luck with the new mod.
 
Larry D. said:
Finney said:
[quote="Bruce B":3fdb6bc9][quote="Nick Prochilo":3fdb6bc9]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:[/quote:3fdb6bc9]

Finney's math is complicated, but his answer is wrong.*
The area of a circle varies directly as the square of its diameter. So, you can just leave out the pi's from the equations and compare the squares of the diameters. For example, a one-inch circle has an area 4 times that of a 1/2 inch circle. Or, 16 times the area of a 1/4 inch circle. For the one inch diameter hole: d^2 = 1.
For the 1/4 inch probe, d^2 = 0.25 x 0.25 = 0.0625, or 6.25% of the area of the one inch hole. And, since we have 3 of those holes, 6.25% divided by 3 equals 2.08% So, your 1/4 inch probe only blocks 2.08% of the vent area of the three one-inch holes.

[smilie=a_tongue.gif]

*Area of 1/4 inch circle: 0.25 inch x 25.4 mm/inch = 6.35 mm dia. or 3.165 mm radius (roughly). A = pi x r^2 or 3.14etc x (3.165) x (3.165) = 31.669 sq. mm., not 82.1699 And 31.669 divided by 1520.122 = 0.0208[/quote:3fdb6bc9]

Larry is correct... I don't know where I came up with the 82.1699 :? Stupid me....
Changing that number to 31.66922 it works out to 2.0833334977937698229097913981192%
 
Unity said:
Bill The Grill Guy said:
okay, I settled it. drilled a hole and stuck a therm in it. Now its done.
How'd you start the hole without (a) centerpunching and chipping more enamel than intended, or (b) skating and skitching all over the lid with a runaway drill? ;)

--John 8)
(You see, I've thought about it, but haven't done it yet. :roll: )

I used 4 layers of masking tape. Started with a very small drill bit and slowley worked my way up to the right size hole. You gotta take it SLOW.
 
Finney said:
Larry D. said:
Finney said:
[quote="Bruce B":289z96hu][quote="Nick Prochilo":289z96hu]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:

Finney's math is complicated, but his answer is wrong.*
The area of a circle varies directly as the square of its diameter. So, you can just leave out the pi's from the equations and compare the squares of the diameters. For example, a one-inch circle has an area 4 times that of a 1/2 inch circle. Or, 16 times the area of a 1/4 inch circle. For the one inch diameter hole: d^2 = 1.
For the 1/4 inch probe, d^2 = 0.25 x 0.25 = 0.0625, or 6.25% of the area of the one inch hole. And, since we have 3 of those holes, 6.25% divided by 3 equals 2.08% So, your 1/4 inch probe only blocks 2.08% of the vent area of the three one-inch holes.

[smilie=a_tongue.gif]

*Area of 1/4 inch circle: 0.25 inch x 25.4 mm/inch = 6.35 mm dia. or 3.165 mm radius (roughly). A = pi x r^2 or 3.14etc x (3.165) x (3.165) = 31.669 sq. mm., not 82.1699 And 31.669 divided by 1520.122 = 0.0208[/quote:289z96hu]

Larry is correct... I don't know where I came up with the 82.1699 :? Stupid me....
Changing that number to 31.66922 it works out to 2.0833334977937698229097913981192%[/quote:289z96hu]

I HATE to throw a wrench in all your equations and figuring.... BUT BUT BUT BUT.......

You have figured the hole for a FLAT SURFACE...now you have to go back and figure it with the degree of curvature in the lid and the vortex factor of which the air rolls against said opening size of hole made....etc....

heh heh heh
 
Smokey_Joe said:
Finney said:
[quote="Larry D.":3moj4t57]
Finney said:
[quote="Bruce B":3moj4t57][quote="Nick Prochilo":3moj4t57]If you stick a 1/4" probe in a 1" hole are you blocking 1/3 of your exhaust of 3 holes?

You're blocking 25% of one 1" hole and 1/4" of 3 1" holes which total 3" so...
you're blocking about 8.33% of your total of 3 inches of exit hole. Hopefully, that will clear things up for you Nick.

:LOL: :LOL:

Bruce's thoughts are right, but his math is wrong.
A 1" dia hole has an area of 506.70748 sqmm
3x that is 1520.12244 sqmm
a 1/4" dia probe has a cross sectional area of 82.16991
divide 82.16991 by 1520.12244 to get 0.054054797059636853989208921881319
multiply 0.054054797059636853989208921881319 by 100
and the answer is that a 1/4" dia probe blocks 5.4% of the opening created by the three 1" dia holes.

Anybody need anything else? :roll:

Finney's math is complicated, but his answer is wrong.*
The area of a circle varies directly as the square of its diameter. So, you can just leave out the pi's from the equations and compare the squares of the diameters. For example, a one-inch circle has an area 4 times that of a 1/2 inch circle. Or, 16 times the area of a 1/4 inch circle. For the one inch diameter hole: d^2 = 1.
For the 1/4 inch probe, d^2 = 0.25 x 0.25 = 0.0625, or 6.25% of the area of the one inch hole. And, since we have 3 of those holes, 6.25% divided by 3 equals 2.08% So, your 1/4 inch probe only blocks 2.08% of the vent area of the three one-inch holes.

[smilie=a_tongue.gif]

*Area of 1/4 inch circle: 0.25 inch x 25.4 mm/inch = 6.35 mm dia. or 3.165 mm radius (roughly). A = pi x r^2 or 3.14etc x (3.165) x (3.165) = 31.669 sq. mm., not 82.1699 And 31.669 divided by 1520.122 = 0.0208[/quote:3moj4t57]

Larry is correct... I don't know where I came up with the 82.1699 :? Stupid me....
Changing that number to 31.66922 it works out to 2.0833334977937698229097913981192%[/quote:3moj4t57]

I HATE to throw a wrench in all your equations and figuring.... BUT BUT BUT BUT.......

You have figured the hole for a FLAT SURFACE...now you have to go back and figure it with the degree of curvature in the lid and the vortex factor of which the air rolls against said opening size of hole made....etc....

heh heh heh[/quote:3moj4t57]

That's why Larry rounded off at the end.
 
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